(x^3+x^2)-(4x-4)=0

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Solution for (x^3+x^2)-(4x-4)=0 equation: 


Simplifying
(x3 + x2) + -1(4x + -4) = 0

Reorder the terms:
(x2 + x3) + -1(4x + -4) = 0

Remove parenthesis around (x2 + x3)
x2 + x3 + -1(4x + -4) = 0

Reorder the terms:
x2 + x3 + -1(-4 + 4x) = 0
x2 + x3 + (-4 * -1 + 4x * -1) = 0
x2 + x3 + (4 + -4x) = 0

Reorder the terms:
4 + -4x + x2 + x3 = 0

Solving
4 + -4x + x2 + x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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